X^2+12x-1280=0

Solution for X^2+12x-1280=0 equation:

X^2+12X-1280=0

a = 1; b = 12; c = -1280;
Δ = b2-4ac
Δ = 122-4·1·(-1280)
Δ = 5264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5264}=\sqrt{16*329}=\sqrt{16}*\sqrt{329}=4\sqrt{329}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{329}}{2*1}=\frac{-12-4\sqrt{329}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{329}}{2*1}=\frac{-12+4\sqrt{329}}{2}
$